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First, we turn the IP address and subnet mask into binary We then draw the first line, the network line, after the last 1 in the mask Now we need to determine how many bits are needed to give us the required number of subnets and hosts We have eight bits to work with (the host portion of the IP address), and we need to determine how many of those are needed to create six subnets One bit would give us two subnets (2n) minus two subnets (the all zeros and all ones subnets), leaving us with no possible subnets That obviously won't work Two bits would give us four subnets (2n) minus two subnets (the all zeros and all ones subnets), leaving us with two possible subnets Closer, but still no cigar Three bits would give us eight subnets (2n) minus two subnets (the all zeros and all ones subnets), leaving us with six possible subnets Bingo Now we need to make sure that we have enough hosts per subnet Because we're using three bits for the subnet, we have five bits left for the host (8 3 = 5) Five bits gives us 32 hosts, minus 2 hosts, leaves us with 30 hosts per subnet Perfect So we will use a 27-bit mask (255255255224) for this network To recap, you can look at the mask determination as a five-step process: 1 Convert the IP address and default mask into binary 2 Draw a line after the last 1 in the subnet mask Everything to the left of this line is your base network address 3 Determine how many bits are required to achieve the desired number of subnets Extend the 1's in your subnet mask by this many bits 4 Draw a second line after the last 1 in the new subnet mask Everything from the left of this line until the first line is the subnet portion Everything to the right of this line is the host portion 5 Make sure the remaining bits in the mask provide enough hosts per subnet That's it To make sure you can perform this task before going forward, let's do a few practice problems Take a look at Exercise 6-3 As usual, the answers are provided on the next page Once you have determined which mask you need to use, the next step is to determine the range of IP addresses that belong to each subnet This is required because you need to know into which subnet a given IP address falls With a simple subnet mask (like 2552552550), it is easy to determine the range If you had the IP address 1721611 with a 2552552550 mask, you know, without doing the binary, that the range of hosts is 1721611 through 172161254 You can also easily recognize that 172162001 and 17216501 are on different subnets However, it is not as easy to recognize that with a 2552552240 mask, 17216341 and 17216731 are on different subnets, while 172161301 and 172161501 are on the same subnet To determine the subnet ranges, we need to do some binary Let's take a look at the process (this process is diagrammed in Figures 6-14 through 6-16) First, we need to take the IP address and mask, convert them into binary, and draw two lines: the network line (right after the last 1 in the default subnet mask, which is determined by the class of IP address), and the subnet line (right after the last 1 in the custom subnet mask) Figure 6-14 details this first step. microsoft.windows.ocr c# exampleBelow is a list of forum posts with OCR projects in various ... is a simple example getting started with LEADTOOLS OCR. ... Language: C# c# ocr pdf fileYou can use WIA library to control the scanning process and tesseractdotnet for OCR. An updated .NET 4.0 version can be found here. object 174 type checking 180 object persistence 180 ObjectAlloc 143 playback feature 143 Objective-C 173 background 173 categories 178 classes 175 data members 176 distributed objects 181 main features 174 PackageMaker 144 page faults reporting 160 PAGER 32 Palette window 64 parent class 175 parent process 151 pasting path at command prompt 304 pathname delimiter 43 colon vs. forward slash 43 Figure 6-14: Step 1 of the ranging process Exercise 6-3: Subnet Mask Determination In the following problems, find the appropriate subnet mask to meet the requirements Do not use a calculator, and remember to start with the default subnet mask for the particular class of address Address 1 2 3 4 5 19216810 1721600 10000 19216810 1721600 Hosts Required 60 2,000 30,000 8 As many as possible Subnets Required 2 28 As many as possible As many as possible 16 c# free ocr library Using Windows Built-in OCR from CSharp - Lost in Details
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15 Jan 2015 ... Diagnostics; namespace ConsoleApplication { class Program { public static void Main(string[] args) { var testImagePath = "./phototest.tif"; if (args.Length > 0) ... Digital Photography: 99 Easy Tips to Make You Look Like a Pro! Answers to Exercise 6-3 1 Mask: 255255255192 (26 bits) Explanation: This is the only mask that meets the criteria 2 Mask: 2552552480 (21 bits) Explanation: This is the only mask that meets the criteria 3 Mask: 2552551280 (17 bits) Explanation: Any mask with less than 18 bits would work, but a 17-bit mask gives us the most subnets (510) 4 Mask: 255255255240 (28 bits) Explanation: Any mask with less than 29 bits would work, but a 28-bit mask gives us the most subnets (14) 5 Mask: 2552552480 (21 bits) Explanation: Any mask with more than 21 bits would work, but a 21-bit mask gives us the most hosts (2,046) emgu ocr c# examplevar Result = Ocr.Read(@"C:\path\to\image.png"); IronOCR is unique in its ability to automatically detect and read text from imperfectly scanned images and PDF documents. ... The OCR (Optical Character Recognition) engine views pages formatted with multiple popular fonts, weights ... c# windows ocrNov 15, 2018 · Image to Text in C#. This repository contains sample C# source code referenced in the tutorial documentation for IronOCR.
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